document.write( "Question 1122003: Robin has a collection of nickels, dimes, and quarters worth $37.50. She has 30 more dimes than nickels and twice as many quarters as dimes. How many coins of each kind does she have?
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Algebra.Com's Answer #738031 by ikleyn(52787)\"\" \"About 
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document.write( "Let x be the number of nickels.\r\n" );
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document.write( "Then the number of dimes is  (x+30)  and the number of quarters is 2*(x+30).\r\n" );
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document.write( "Nickels   contribute    5x          cents to the total.\r\n" );
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document.write( "Dimes     contribute    10*(x+30)   cents to the total.\r\n" );
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document.write( "Quarters  contribute    25*2*(x+30) cents to the total.\r\n" );
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document.write( "So, your \"money\" equation is\r\n" );
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document.write( "    5x + 10*(x+30) + 50*(x+30) = 3750    cents.\r\n" );
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document.write( "Simplify and solve for x:\r\n" );
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document.write( "    5x + 10x + 300 + 50x + 1500 = 3750\r\n" );
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document.write( "    65x = 3750 - 300 - 1500\r\n" );
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document.write( "    65x = 1950  ====>  x = \"1950%2F65\" = 30.\r\n" );
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document.write( "Answer.  30 nickels;  30+30 = 60 dimes;  and  2*60 = 120 quarters.\r\n" );
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document.write( "Check.   30*5 + 60*10 + 120*25 =  3750  cents.    ! Correct !\r\n" );
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document.write( "    This problem is for one unknown and one equation.\r\n" );
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