document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=14859>Question 14859</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 7a-3=3-2a<BR>\n" );
document.write( "This is what we came up with.  Not coming out right.<BR>\n" );
document.write( "7a-3+3=3-2a+3<BR>\n" );
document.write( "7a=2a  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #7380 by </B><A HREF=/tutors/aboutme.mpl?userid=jb007mi6><B>jb007mi6(53)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jb007mi6><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=7380\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> so you have 7a-3=3-2a so first I would add 2a to both sides so I get\r<BR>\n" );
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document.write( "7a-3+2a=3-2a+2a\r<BR>\n" );
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document.write( "this boils down to\r<BR>\n" );
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document.write( "9a-3=3\r<BR>\n" );
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document.write( "add 3 to both sides and get\r<BR>\n" );
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document.write( "9a-3+3=3+3\r<BR>\n" );
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document.write( "this boils down to\r<BR>\n" );
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document.write( "9a=6\r<BR>\n" );
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document.write( "divide both sides by 9, and you get 9a/9=6/9 \r<BR>\n" );
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document.write( "so a=2/3\r<BR>\n" );
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document.write( "hope this helps </SPAN>\n" );
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