document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1121964>Question 1121964</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given that x, x/2 and x/4 is a geometric progression. Find the sum of the 1st 11 terms of the GP.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #737985 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13209)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=737985\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Sum of the first 2 terms:<BR>\n" );
document.write( "x + x/2 = x(1+1/2) = x(2-1/2)<br><BR>\n" );
document.write( "Sum of the first 3 terms:<BR>\n" );
document.write( "x+x/2+x/4 = x(1+1/2+1/4) = x(2-1/4)<br><BR>\n" );
document.write( "Sum of the first 4 terms:<BR>\n" );
document.write( "x+x/2+x/4+x/8 = x(1+1/2+1/4+1/8) = x(2-1/8)<br><BR>\n" );
document.write( "...<BR>\n" );
document.write( "look at the pattern...<BR>\n" );
document.write( "...<br><BR>\n" );
document.write( "Sum of the first 11 terms:<BR>\n" );
document.write( "x+x/2+x/4+...+x/2^10 = ... = x(2-1/2^10) = x(2-1/1024) = (2047/1024)x<BR>\n" );
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document.write( "</TD></TR></TABLE>\n" );