document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1121881>Question 1121881</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A new machine can produce three more than twice the production per hour of the old machine. If the new machine can produce 187 units per hour, how many did the old machine produce?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #737883 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=737883\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x = the production per hour of the old machine.\r<BR>\n" );
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document.write( "the production per hour of the new machine is three more than twice the production per hour of the old machine.\r<BR>\n" );
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document.write( "that makes the production per hour of the new machine equal to 3 * x + 3.\r<BR>\n" );
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document.write( "the new machine can produce 187 units per hour.\r<BR>\n" );
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document.write( "your equation becomes 187 = 2 * x + 3\r<BR>\n" );
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document.write( "subtract c from both sides of this equation to get 184 = 2 * x\r<BR>\n" );
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document.write( "solve for x to get x = 184 / 2 = 92.\r<BR>\n" );
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document.write( "the old machine can product 92 units per hour.\r<BR>\n" );
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document.write( "the new machine can produce three more than twice this = 2 * 92 + 3 = 184 + 3 = 187 units per hour.\r<BR>\n" );
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