document.write( "Question 101328: Tutor, \r
\n" ); document.write( "\n" ); document.write( "I do not think I am understanding how to solve this problem could you please help me? \r
\n" ); document.write( "\n" ); document.write( "Find the distance between each pair of points: \r
\n" ); document.write( "\n" ); document.write( "(-3,0) and (4,0)\r
\n" ); document.write( "\n" ); document.write( "Any explanation would help me with this problem. Thanks.
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Algebra.Com's Answer #73788 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Start with the given distance formula\r
\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%28x%5B1%5D-x%5B2%5D%29%5E2%2B%28y%5B1%5D-y%5B2%5D%29%5E2%29\" where is the first point and is the second point \r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%28-3-4%29%5E2%2B%280-0%29%5E2%29\" Plug in \"x%5B1%5D=-3\", \"x%5B2%5D=4\", \"y%5B1%5D=0\", \"y%5B2%5D=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%28-7%29%5E2%2B%280%29%5E2%29\" Evaluate \"-3-4\" to get -7. Evaluate \"0-0\" to get 0. \r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%2849%2B0%29\" Square each value\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%2849%29\" Add\r
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\n" ); document.write( "\n" ); document.write( "\"d=7\" Simplify the square root (note: If you need help with simplifying the square root, check out this solver)\r
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\n" ); document.write( "\n" ); document.write( "So the distance between (-3,0) and (4,0) is 7 units
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