document.write( "Question 1121868: The sum of paul and beth’s ages is 67. Eight
\n" ); document.write( " years ago paul was twice as old as beth. How old is each now?
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Algebra.Com's Answer #737865 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
\"system%28p%2Bb=67%2Cp-8=2%28b-8%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"highlight%28b=25%29\"-----Beth
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\n" ); document.write( "\"highlight%28p=42%29\"-----Paul\r
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\n" ); document.write( "\n" ); document.write( "p, Paul's age now
\n" ); document.write( "b, Beth's age now\r
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\n" ); document.write( "\n" ); document.write( "The description translated literally is this system:
\n" ); document.write( "\"system%28p%2Bb=67%2Cp-8=2%28b-8%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "Second Equation Simplification,
\n" ); document.write( "\"p-8=2b-16\"
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\n" ); document.write( "\n" ); document.write( "Substitute this into the age-sum equation:
\n" ); document.write( "\"p%2Bb=67\"
\n" ); document.write( "\"%282b-8%29%2Bb=67\"
\n" ); document.write( "\"3b-8=67\"
\n" ); document.write( "\"3b=75\"
\n" ); document.write( "\"b=25\"-------Beth's age is found.
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