document.write( "Question 1121843: The stage of a rocket burns 28s longer than the second stage. If the total burning time for both stages is 152 s how long does each stage burn? \n" ); document.write( "
Algebra.Com's Answer #737841 by ikleyn(52914) You can put this solution on YOUR website! . \n" ); document.write( "The \n" ); document.write( "If the total burning time for both stages is 152 s how long does each stage burn? \n" ); document.write( "~~~~~~~~~~~~~~~~~~~\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "From the condition, you have these two equations\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "x + y = 152 (1) (x = the first stage burning time)\r\n" ); document.write( "x - y = 28 (2)\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Add the two equations. You will get \r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "2x = 152 + 28 = 180 ====> x = 90 seconds for the first stage.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Then y = 152 - 90 = 62 seconds for the seconf stage.\r\n" ); document.write( "\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Solved.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |