document.write( "Question 1121834: Solve the eq on the interval [0,2pi) : sin2x-cosx=0\r
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document.write( "I used the indetity sin2x = 2sinxcosx\r
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document.write( "So 2sinxcosx-cosx=0
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document.write( "Cosx(2sinx-1) = 0\r
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document.write( "Thus cosx=0 and 2sinx-1=0\r
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document.write( "Simplified im left with these to evaluate
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document.write( "Where is cosx = 0 and where is sinx= -1/2\r
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document.write( "Cosx = 0 at 3pi/2 and pi/2
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document.write( "Sinx = -1/2 at 7pi/ and 11pi/6\r
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document.write( "Would those be my values? \n" );
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