document.write( "Question 1121807: Rationalize the function and give its domain in interval notation:
\n" ); document.write( "F(x) = \"+%282%2Bsqrt%28x-3%29%29%2F%285%2Bsqrt%28x-3%29%29+\"\r
\n" ); document.write( "\n" ); document.write( "So far for my work: I first, multiplied by the conjugate; \"+5-sqrt%28x-3%29+\"\r
\n" ); document.write( "\n" ); document.write( "I ended up with \"+%28x%2B13%2B3sqrt%28x-3%29%29+%2F+%28x%2B28%29+\"\r
\n" ); document.write( "\n" ); document.write( "I don’t think that’s right and I’m having trouble knowing what the correct answer is as my text does not have this answer solution to check.
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Algebra.Com's Answer #737799 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
\"%282%2Bsqrt%28x-3%29%29%2F%285%2Bsqrt%28x-3%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "Yes, multiply the entire expression by \"1=%285-sqrt%28x-3%29%29%2F%285-sqrt%28x-3%29%29\", and simplify from that multiplication.\r
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\n" ); document.write( "\n" ); document.write( "Result of that after simplification should be
\n" ); document.write( "\"F%28x%29=%28-x%2B13%2B3sqrt%28x-3%29%29%2F%2828-x%29\"\r
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\n" ); document.write( "\n" ); document.write( "Or if multiply again by \"1=%28-1%29%2F%28-1%29\" you could have as
\n" ); document.write( "\"highlight%28F%28x%29=%28x-13-3sqrt%28x-3%29%29%2F%28x-28%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "-\r
\n" ); document.write( "\n" ); document.write( "The radical forces the restriction \"x%3E=3\" and the denominator cannot be allowed 0, so forces the restriction \"x%3C%3E28\".
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