document.write( "Question 1121788: Two angles form a linear pair. The measure of one angle is 26∘ greater than the measure of the other angle. Find the measure of each angle.
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Algebra.Com's Answer #737770 by MathLover1(20850) $\"\"$ $\"About$

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the two angles which form a linear pair are supplementary, they always add to $\"180\"$ ° \r
\n" ); document.write( "\n" ); document.write( "let's say one angle is $\"alpha\"$ and the other angle is $\"beta\"$ \r
\n" ); document.write( "\n" ); document.write( "by definition, $\"alpha%2Bbeta=180\"$ ° ........eq.1\r
\n" ); document.write( "\n" ); document.write( "if the measure of one angle is $\"26\"$ ° greater than the measure of the other angle, we have\r
\n" ); document.write( "\n" ); document.write( " $\"alpha=beta%2B26\"$ °....eq.2\r
\n" ); document.write( "\n" ); document.write( "substitute $\"alpha\"$ from eq.2 in eq.1\r
\n" ); document.write( "\n" ); document.write( " $\"beta%2B26%2Bbeta=180\"$ ° ........solve for $\"beta\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"2beta=%28180-26%29\"$ °\r
\n" ); document.write( "\n" ); document.write( " $\"2beta=154\"$ °\r
\n" ); document.write( "\n" ); document.write( " $\"beta=154%2F2\"$ °\r
\n" ); document.write( "\n" ); document.write( " $\"highlight%28beta=+77%29\"$ °\r
\n" ); document.write( "\n" ); document.write( "go to eq.2 and calculate $\"alpha\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"alpha=beta%2B26\"$ °....eq.2\r
\n" ); document.write( "\n" ); document.write( " $\"alpha=%2877%2B26%29\"$ °\r
\n" ); document.write( "\n" ); document.write( " $\"highlight%28alpha=103%29\"$ °\r
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