document.write( "Question 1121771: Faith normally saves £2.50 a week. She decides to save up for a new bicycle and increases her savings such that she now puts a total of £4.50 a week aside. The bicycle costs £300. How much sooner (to the nearest week) will faith be able to purchase her bicycle assuming she begins with no savings? \n" ); document.write( "
Algebra.Com's Answer #737758 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "(1) 300/2.50 = 120; 120 weeks if saving 2.50 per week. \n" ); document.write( "300/4.50 = 66 2/3; 66 2/3 weeks if saving 4.50 per week. \n" ); document.write( "difference: 120-66 2/3 = 53 1/3. \n" ); document.write( "She will be able to purchase the bicycle 53 1/3 weeks sooner. \n" ); document.write( "or... \n" ); document.write( "(2) 300/2.50 = 120; 120 weeks if she continued saving 2.50 per week. \n" ); document.write( "4.50/2.50 = 9/5; she decides to save 9/5 as much each week. \n" ); document.write( "It will then take her 5/9 as long to save the required amount. \n" ); document.write( "120*(5/9) = 600/9 = 66 2/3. \n" ); document.write( "120 - 66 2/3 = 53 1/3 \n" ); document.write( "Obviously the same answer as by the other method. \n" ); document.write( " |