document.write( "Question 1121753: How do you find domain of A(x)=sqrt(9-x^2)? \n" ); document.write( "

Algebra.Com's Answer #737744 by ikleyn(52787) $\"\"$ $\"About$

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document.write( "The expression under the square root must be non-negative\r\n" );
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document.write( "9 - x^2 >= 0,   or\r\n" );
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document.write( "9 >= x^2,    which implies\r\n" );
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document.write( "-3 <= x <= 3.\r\n" );
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document.write( "Answer.  The domain is the set  { -3 <= x <= 3},   or in the interval notation,  [-3,3].\r\n" );
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\n" ); document.write( "\n" ); document.write( "For many other similar solved problem see the lesson\r
\n" ); document.write( "\n" ); document.write( " - Domain of a function which involves a quadratic polynomial under the square root operator,\r
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