document.write( "Question 1121755: Solve the equation on the interval [0, 2pi)\r
\n" ); document.write( "\n" ); document.write( "\"sqrt%283%29\" tan^2 x = \"3tanx\"\r
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Algebra.Com's Answer #737737 by ikleyn(52810)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "\"sqrt%283%29\" tan^2  x = \"3tanx\"  ====>   divide both sides by \"sqrt%283%29\"  ====>\r\n" );
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document.write( "tan^2(x) = \"sqrt%283%29%2Atan%28x%29\"\r\n" );
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document.write( "\"tan%5E2%28x%29+-+sqrt%283%29%2Atan%28x%29\" = 0\r\n" );
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document.write( "\"tan%28x%29%2A%28tan%28x%29+-+sqrt%283%29%29\" = 0\r\n" );
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document.write( "This equation deploys in two separate equations:\r\n" );
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document.write( "    1)  tan(x) = 0,  which has two solutions in the given interval:  x= 0  and  x= \"pi\";\r\n" );
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document.write( "and\r\n" );
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document.write( "    2)  tan(x) = \"sqrt%283%29\",  which also has two solutions in the given interval  x= \"pi%2F3\"  and  x= \"4pi%2F3\".\r\n" );
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document.write( "Answer.  The original equation has 4 solutions in the given interval:\r\n" );
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document.write( "                0,  \"pi\",  \"pi%2F3\"  and  \"4pi%2F3\".\r\n" );
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