document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1121733>Question 1121733</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In ABC, A=45 degrees, b=15 cm and c=22 cm. Find the area of the triangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #737720 by </B><A HREF=/tutors/aboutme.mpl?userid=ikleyn><B>ikleyn(52795)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ikleyn><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ikleyn><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=737720\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .\r<BR>\n" );
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document.write( "You can solve it in much more easy way.\r<BR>\n" );
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document.write( "In this problem, two side lengths of the triangle are given and the angle concluded between these two sides.\r\n" );
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document.write( "Then the area of the triangle is equal to \r\n" );
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document.write( "    A = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%281%2F2%29%2Ab%2Ac%2Asin%28A%29 ALIGN=MIDDLE  ALT=\"%281%2F2%29%2Ab%2Ac%2Asin%28A%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%281%2F2%29%2A15%2A22%2A%28sqrt%282%29%2F2%29 ALIGN=MIDDLE  ALT=\"%281%2F2%29%2A15%2A22%2A%28sqrt%282%29%2F2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > = 116.67 cm^2.\r\n" );
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document.write( "On formulas for the area of a triangle see the lesson\r<BR>\n" );
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document.write( "&nbsp;&nbsp;&nbsp;&nbsp;- <A  rel=nofollow HREF=http://www.algebra.com/algebra/homework/Surface-area/Formulas-for-area-of-a-triangle.lesson>Formulas for area of a triangle</A>, \r<BR>\n" );
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document.write( "in this site.\r<BR>\n" );
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