document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1121733>Question 1121733</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In ABC, A=45 degrees, b=15 cm and c=22 cm. Find the area of the triangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #737714 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=737714\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find a by Law of Cosines: <BR>\n" );
document.write( "a^2=b^2+c^2-2bc cos A<BR>\n" );
document.write( "a^2=225+484-2(330) cos 45<BR>\n" );
document.write( "=709-660(0.7071)=709-466.69=242.31<BR>\n" );
document.write( "sqrt(242.31)=15.6 (rounded)<BR>\n" );
document.write( "length of all 3 sides combined is 52.6 and half of it, 26.3, is s<BR>\n" );
document.write( "sqrt(s*(s-a)(s-b)(s-c))=sqrt(26.3*11.3*4.3*10.7)=sqrt (13673.71)<BR>\n" );
document.write( "=116.9 cm^2 (Hero's Formula) </SPAN>\n" );
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