document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=101307>Question 101307</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A 30% salt solution is prepared by mixing a 20% salt solution and a 45% salt solution.  How many litres of each must be used to produce 60 L of the 30% salt solution?   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #73767 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=73767\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A 30% salt solution is prepared by mixing a 20% salt solution and a 45% salt solution.  How many litres of each must be used to produce 60 L of the 30% salt solution?  <BR>\n" );
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document.write( "Let amt of 20% solution be \"x\" L ; amt of active ingredient = 0.20x L<BR>\n" );
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document.write( "Amt of 45% solution is \"60-x\" L ;amt active is 0.45(60-x)= 27-0.45x L<BR>\n" );
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document.write( "Amt of 30% mixture is 60 L; amt active is 18 L<BR>\n" );
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document.write( "EQUATION<BR>\n" );
document.write( "0.20x + 27 - 0.45x = 18<BR>\n" );
document.write( " -0.15x = -7<BR>\n" );
document.write( "x = 46.67 L (amt of 20% solution)<BR>\n" );
document.write( "60-x = 13.33 L (amt of 45% solution)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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