document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1120410>Question 1120410</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi, I need some help with this problem: \r<BR>\n" );
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document.write( "\"2^{n+3}+2^{3n-2}+2^{5n+1}=32\"\r<BR>\n" );
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document.write( "Thanks! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #737649 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=737649\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> At least as written, there is no set formula to solve this.<BR>\n" );
document.write( "If the terms on the left were multiplied together, then log to base 2 of both sides could be used.\r<BR>\n" );
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document.write( "One can graph this to solve.<BR>\n" );
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document.write( "x=0.643 </SPAN>\n" );
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