document.write( "Question 101054: Please help me complete the ordered pairs so that each is a solution for the given equation.\r
\n" ); document.write( "\n" ); document.write( "3x + 4y + 12 = (0, ),(3/4),( , 0), (8/3),\r
\n" ); document.write( "\n" ); document.write( "Thanxs
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Algebra.Com's Answer #73762 by elima(1433)\"\" \"About 
You can put this solution on YOUR website!
You would just plug into the equation the given value and solve for the y or x; for instance the first one is given your x value, so substitute that value for x in the equation and solve for y;
\n" ); document.write( "3x+4y+12=0
\n" ); document.write( "I would begin by subtracting 12 from both sides;
\n" ); document.write( "3x+4y=-12
\n" ); document.write( "3(0)+4y=-12
\n" ); document.write( "4y=-12
\n" ); document.write( "y=-3
\n" ); document.write( "So the first ordered pair would be (0,-3)
\n" ); document.write( "I'm not sure if the next given value is for x or y, but you would do the same thing as I did. I will do it as a y value;
\n" ); document.write( "\"3x%2B4%283%2F4%29=-12\"
\n" ); document.write( "\"3x%2B%2812%2F4%29=-12\"
\n" ); document.write( "3x+3=-12
\n" ); document.write( "3x=-9
\n" ); document.write( "x=-3
\n" ); document.write( "so the ordered pair would be (-3,3/4)
\n" ); document.write( "If it is not the y value then solve the equation using that as x value and solve for y.
\n" ); document.write( ":)
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