document.write( "Question 101054: Please help me complete the ordered pairs so that each is a solution for the given equation.\r
\n" );
document.write( "\n" );
document.write( "3x + 4y + 12 = (0, ),(3/4),( , 0), (8/3),\r
\n" );
document.write( "\n" );
document.write( "Thanxs \n" );
document.write( "
Algebra.Com's Answer #73762 by elima(1433)![]() ![]() ![]() You can put this solution on YOUR website! You would just plug into the equation the given value and solve for the y or x; for instance the first one is given your x value, so substitute that value for x in the equation and solve for y; \n" ); document.write( "3x+4y+12=0 \n" ); document.write( "I would begin by subtracting 12 from both sides; \n" ); document.write( "3x+4y=-12 \n" ); document.write( "3(0)+4y=-12 \n" ); document.write( "4y=-12 \n" ); document.write( "y=-3 \n" ); document.write( "So the first ordered pair would be (0,-3) \n" ); document.write( "I'm not sure if the next given value is for x or y, but you would do the same thing as I did. I will do it as a y value; \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "3x+3=-12 \n" ); document.write( "3x=-9 \n" ); document.write( "x=-3 \n" ); document.write( "so the ordered pair would be (-3,3/4) \n" ); document.write( "If it is not the y value then solve the equation using that as x value and solve for y. \n" ); document.write( ":) \n" ); document.write( " |