document.write( "Question 1121642: How do you determine whether is an even, odd, or neither and what is its symmetry?\r
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document.write( "If I recall correctly even tests are f(-x) = f(x), odd tests are f(-x) = -f(x) and even has a symmetry in respects to the y-axis and odd to the origin? But I don't know how to approach the above function. \n" );
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Algebra.Com's Answer #737601 by MathLover1(20850)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "even tests are \n" ); document.write( "\n" ); document.write( "given: \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "so, \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "odd tests are \n" ); document.write( "\n" ); document.write( "since above is proven that f(-x) = -f(x), means f(x) = (x^2 + 1)/x is an \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since the function is \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |