document.write( "Question 1121642: How do you determine whether \"+f%28x%29+=+%28X%5E2%2B1%29%2F%28x%29\" is an even, odd, or neither and what is its symmetry?\r
\n" ); document.write( "\n" ); document.write( "If I recall correctly even tests are f(-x) = f(x), odd tests are f(-x) = -f(x) and even has a symmetry in respects to the y-axis and odd to the origin? But I don't know how to approach the above function.
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Algebra.Com's Answer #737601 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "even tests are\"+f%28-x%29+=+f%28x%29\", \r
\n" ); document.write( "\n" ); document.write( "given: \"f%28x%29=%28x%5E2%2B1%29%2Fx+\"\r
\n" ); document.write( "\n" ); document.write( "\"f%28-x%29=%28%28-x%29%5E2%2B1%29%2F%28-x%29\"\r
\n" ); document.write( "\n" ); document.write( "\"f%28-x%29+=+-%28x%5E2%2B1%29%2Fx+\"=> \"+f%28-x%29+=+-f%28x%29\"\r
\n" ); document.write( "\n" ); document.write( "so, \"f%28-x%29+%3C%3E+f%28x%29++\"=> \"f%28x%29=%28x%5E2%2B1%29%2Fx\" is \"not\" an even function\r
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\n" ); document.write( "\n" ); document.write( "odd tests are \"f%28-x%29+=+-f%28x%29\"\r
\n" ); document.write( "\n" ); document.write( "since above is proven that f(-x) = -f(x), means f(x) = (x^2 + 1)/x is an \"odd\" function\r
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\n" ); document.write( "\n" ); document.write( "Since the function is \"+odd\", it is symmetric about the \"origin\".\r
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\n" ); document.write( "\n" ); document.write( "\"+graph%28+600%2C+600%2C+-10%2C+10%2C+-10%2C+10%2C+%28x%5E2%2B1%29%2Fx%29+\"\r
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