document.write( "Question 1121572: A journal polled its readers to determine the proportion of wives who, if given a second chance, would marry their husband again.
\n" ); document.write( "According to the responses from the survey, 72% of wives would marry their husbands again.\r
\n" ); document.write( "\n" ); document.write( "Suppose a random and independent sample of 5 wives was collected. Define the random variable X as the number of these wives who would marry their husbands again. Use the binomial distribution to find the probability that at most 4 of the wives sampled said they would marry their husbands again.\r
\n" ); document.write( "\n" ); document.write( "Select one:
\n" ); document.write( "a. 0.998279
\n" ); document.write( "b. 0.806508
\n" ); document.write( "c. 0.376234
\n" ); document.write( "d. 0.193492\r
\n" ); document.write( "\n" ); document.write( "Thanks in advance
\n" ); document.write( "

Algebra.Com's Answer #737490 by FrankM(1040)\"\" \"About 
You can put this solution on YOUR website!
\"At most, 4\" is the same result as 1-P(5), i.e. 1 minus the chance that all 5 said yes. Which makes the math simpler.\r
\n" ); document.write( "\n" ); document.write( "1-(.72)^5=1-.19349= .806508 (b)
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