document.write( "Question 1121545: The total number of pens in boxes X Y Z is 300.Y has 50 percent of the pens in Z. Bob takes out one third of the pens in X trebles the number of pens in Y and puts 40 more pens in Z. Now each box has the same number of pens. Find the total number of pens now.\r
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Algebra.Com's Answer #737483 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "Box Y has half as many as box Z, so...

\n" ); document.write( "let n = number in box Y
\n" ); document.write( "then 2n = number in box Z

\n" ); document.write( "Since the total number in the three boxes is 300...

\n" ); document.write( "then 300-3n = number in box X

\n" ); document.write( "Now Bob takes 1/3 of the pens out of box X; the number now in box X is

\n" ); document.write( "(300-3n)-(1/3)(300-3n) = 200-2n

\n" ); document.write( "He also triples the number in box Y; the number now in box Y is 3n.

\n" ); document.write( "We know that X and Y now have the same number, so

\n" ); document.write( "200-2n = 3n
\n" ); document.write( "200 = 5n
\n" ); document.write( "n = 40

\n" ); document.write( "The number now in boxes X and Y is 3n = 200-2n = 120.

\n" ); document.write( "Then, since we know all three boxes now have the same number, the total now is 360.
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