document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1121545>Question 1121545</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The total number of pens in boxes X Y Z is 300.Y has 50 percent of the pens in Z.  Bob takes out one third of the pens in X trebles the number of pens in Y and puts 40 more pens in Z. Now each box has the same number of pens. Find the total number of pens now.\r<BR>\n" );
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document.write( "thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #737475 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=737475\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x+y+z=300<BR>\n" );
document.write( "y=(1/2)z<BR>\n" );
document.write( "(2/3)x=3y=(z+40)<BR>\n" );
document.write( "(2/3)x=(3/2)z=z+40<BR>\n" );
document.write( "can solve for z<BR>\n" );
document.write( "(1/2)z=40<BR>\n" );
document.write( "z=80 pens<BR>\n" );
document.write( "y=40 pens<BR>\n" );
document.write( "(2/3)x=120 pens, x=180 pens  (180, 40, 80)<BR>\n" );
document.write( "Now they each have 120 pens, and the total is 360 pens. (120, 120, 120)<BR>\n" );
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