document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=101255>Question 101255</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Let u=<-1,3> and v=<4,-6>.  <BR>\n" );
document.write( "Find each of the following:\r<BR>\n" );
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document.write( "a. 3u-2v<BR>\n" );
document.write( "b. The normalization of v </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #73747 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=73747\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let u=<-1,3> and v=<4,-6>. <BR>\n" );
document.write( "Find each of the following: <BR>\n" );
document.write( "a. 3u-2v = 3(-1,3)-2(4,-6)=(-3-8.9+12)=(-11,21)<BR>\n" );
document.write( "b. The normalization of v:<BR>\n" );
document.write( "|v|= sqrt(4^2+6^2) = sqrt52 = 2sqrt13<BR>\n" );
document.write( "So, norm of v = (4/(2sqrt13),-6/(2sqrt13))<BR>\n" );
document.write( "===============<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
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