document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=101254>Question 101254</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Write in trig form:  -6 + 6sqrt3i </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #73746 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=73746\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Write in trig form:  -6 + 6sqrt3i<BR>\n" );
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document.write( "Conversion formulas:<BR>\n" );
document.write( "r = sqrt(a^2+b^2)<BR>\n" );
document.write( "theta = tan^-1(b/a)<BR>\n" );
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document.write( "Your Problem:<BR>\n" );
document.write( "r = sqrt((-6)^2+(6sqrt3)^2)= sqrt(36+108)= 12<BR>\n" );
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document.write( "theta = tan^-1(6sqrt3/-6) = tan^-1(-sqrt3)=(2/3)pi<BR>\n" );
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document.write( "Trig form:<BR>\n" );
document.write( "-6+6sqrt3i = 12(cos((2/3)pi) + isin((2/3)pi)<BR>\n" );
document.write( "============<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );