document.write( "Question 1121479: In a survey of 6000 ;women, 3431 say they change their nail polish once a week. Construct a 99 % confidence interval for the population proportion of women who change their nail polish once a week.
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document.write( "A 99% confidence interval for the population proportion is (
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document.write( "nothing,
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document.write( "(Round to three decimal places as needed.) \n" );
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Algebra.Com's Answer #737421 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! point estimate is 3431/6000=0.572 \n" ); document.write( "CI is 0.572+/- z*SE, the second part is 2.576*sqrt(p*(1-p)/n) sqrt(0.245/6000)=0.0064 \n" ); document.write( "CI half-interval is 0.0165 or 0.017 \n" ); document.write( "(0.555, 0.589) \n" ); document.write( " |