document.write( "Question 1121449: a) Find the value of xyz, given that xy = 117, yz = 286 and xz = 198.
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document.write( "b) Hence, find the values of x, y and z. \n" );
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Algebra.Com's Answer #737379 by greenestamps(13206) You can put this solution on YOUR website! \n" ); document.write( "Without context, the problem PROBABLY is looking for a solution in positive integers. However, if (a,b,c) is a solution, then (-a,-b,-c) is also a solution. \n" ); document.write( "The problem seems to suggest finding the product xyz first and then using that to find x, y, and z separately. \n" ); document.write( "That can be done; but the arithmetic gets ugly. It is far easier to find the values of x, y, and z and then find the value of the product xyz. \n" ); document.write( "The values of the separate variables can be found easily by trial and error, by looking at the possible factorizations of the three given products. \n" ); document.write( "For me, the first thing I see is 117 = 9*13. \n" ); document.write( "Then, having one number that has a factor of 9, I look for another; 198 = 9*22. \n" ); document.write( "And trying 13*22 for the third product gives me the right result, 286. \n" ); document.write( "So the solution in positive integers is 9, 13, and 22. \n" ); document.write( "Finding the product of all three numbers is then simple arithmetic. \n" ); document.write( " |