document.write( "Question 1121449: a) Find the value of xyz, given that xy = 117, yz = 286 and xz = 198.
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Algebra.Com's Answer #737336 by rothauserc(4718)\"\" \"About 
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y = 117/x, y = 286/z
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\n" ); document.write( "117/x = 286/z
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\n" ); document.write( "117z = 286x
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\n" ); document.write( "z = 286x/117
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\n" ); document.write( "note that xz = 198, therefore
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\n" ); document.write( "z = 198/x, and
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\n" ); document.write( "198/x = 286x/117
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\n" ); document.write( "286x^2 = 198 * 117
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\n" ); document.write( "x^2 = 198 * 117 /286 = 81
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\n" ); document.write( "x = 9 or -9
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\n" ); document.write( "using given relationships and x = 9
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\n" ); document.write( "9y = 117
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\n" ); document.write( "y = 13
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\n" ); document.write( "9z = 198
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\n" ); document.write( "z = 22
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\n" ); document.write( "there are two solutions
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\n" ); document.write( "x = 9, y = 13, z = 22, xyz = 9 * 13 * 22 = 2574
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\n" ); document.write( "x = -9, y = -13, z = -22, xyz = -9 * -13 * -22 = -2574
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