document.write( "Question 1121374: Find three positive consecutive integers such that the product of the first and second is equal to two more than ten times the third integer. \n" ); document.write( "
Algebra.Com's Answer #737228 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! integers are x, x+1, and x+2 \n" ); document.write( "x(x+1)=10(x+2)+2 \n" ); document.write( "x^2+x=10x+20+2 \n" ); document.write( "x^2-9x-22=0 \n" ); document.write( "(x-11)(x+2)=0 \n" ); document.write( "x=11, only positive result\r \n" ); document.write( "\n" ); document.write( "11,12,13 \n" ); document.write( "product of first two is 132, which is 2 more than 10 times the third. \n" ); document.write( " |