document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1120407>Question 1120407</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In a sample of 800 U.S.&#8203; adults, 189 dine out at a resaurant more than once per week. Two U.S. adults are selected at random from the population of all U.S. adults without replacement. Assuming the sample is representative of all U.S.&#8203; adults, complete parts&#8203; (a) through&#8203; (d).<BR>\n" );
document.write( "A) find the probability that both adults dine out more than once per week \r<BR>\n" );
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document.write( "B)find the probability that neither adult dines out more than once per week <BR>\n" );
document.write( "C)find the probability that at least one of the two adults done that more than once per week and <BR>\n" );
document.write( "D)which of the events can be considered unusual all answers must be rounded to three decimal places as needed </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #737196 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=737196\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a.  (189/800)*(188/799)=0.056<BR>\n" );
document.write( "b. (611/800)*(610/799)=0.583<BR>\n" );
document.write( "c, 1-neither means at least 1, or 0.417\r<BR>\n" );
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document.write( "If one considers the 5% level as being unusual, none is.<BR>\n" );
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