document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1120593>Question 1120593</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Complete parts&#8203; (a) and&#8203; (b) using the probability distribution below.<BR>\n" );
document.write( "The number of overtime hours worked in one week per employee\r<BR>\n" );
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document.write( "Overtime hours---0---6 on the below numbers<BR>\n" );
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document.write( "Probability---0.015----0.096 on the below numbers<BR>\n" );
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document.write( "0----0.015\r<BR>\n" );
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document.write( "1----0.066\r<BR>\n" );
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document.write( "2---0.172\r<BR>\n" );
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document.write( "3----0.273\r<BR>\n" );
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document.write( "4----0.237\r<BR>\n" );
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document.write( "5-----0.141\r<BR>\n" );
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document.write( "6-----0.096\r<BR>\n" );
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document.write( "&#8203;(a) Find the&#8203; mean, variance, and standard deviation of the probability distribution.\r<BR>\n" );
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document.write( "Find the mean of the probability distribution._______ </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #737182 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=737182\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The mean is the sum of all integers * their probability <BR>\n" );
document.write( "0+0.066+0.344+0.819<BR>\n" );
document.write( "0.948+0.705+0.576=3.458 mean\r<BR>\n" );
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document.write( "variance is the sum of the difference between the integer and the mean * probability<BR>\n" );
document.write( "3.458^2*0.015=0.1794<BR>\n" );
document.write( "2.458^2*0.066=0.3988<BR>\n" );
document.write( "1.458^2*0.172=0.3656<BR>\n" );
document.write( "0.458^2*0.273=0.0573<BR>\n" );
document.write( "0.542^2*0.237=0.0696<BR>\n" );
document.write( "1.542^2*0.141=0.3353<BR>\n" );
document.write( "2.542^2*0.096=0.6203<BR>\n" );
document.write( "sum is 2.0263 variance\r<BR>\n" );
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document.write( "sd is sqrt (2.0263)=1.423  standard deviation </SPAN>\n" );
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