document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1121300>Question 1121300</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Resuelve factorizando la ecuacion: 0=ื^2-3ื-108<BR>\n" );
document.write( "(Mas entendible: 0=ืal cuadrado-3ื-108 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #737124 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=737124\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the quadratic equation is x^2 - 3x - 108 = 0\r<BR>\n" );
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document.write( "108 / 2 = 54<BR>\n" );
document.write( "54 - 2 is not equal to 3.\r<BR>\n" );
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document.write( "108 / 3 = 36<BR>\n" );
document.write( "36 - 3 is not equal to 3.\r<BR>\n" );
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document.write( "108 / 6 = 18<BR>\n" );
document.write( "18 - 6 is not equal to 3\r<BR>\n" );
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document.write( "108 / 9 = 12<BR>\n" );
document.write( "12 - 9 is equal to 3, therefore this combination should work.\r<BR>\n" );
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document.write( "since the constant term is negative, then it's going to be 12 * -9 or it's going to be 9 * -12.\r<BR>\n" );
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document.write( "either one will get you -108.\r<BR>\n" );
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document.write( "since the middle term is negative, then it can't be 12 - 3 becausee that's positive.\r<BR>\n" );
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document.write( "it has to be 9 - 12 = -3.\r<BR>\n" );
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document.write( "therefore the factors have to be (x - 12) * (x + 9).\r<BR>\n" );
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document.write( "when you multiply these factors out, you get:\r<BR>\n" );
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document.write( "(x - 12) * (x + 9) = x^2 + 9x - 12x - 108\r<BR>\n" );
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document.write( "combine like terms to get x^2 - 3x - 108.\r<BR>\n" );
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document.write( "either one of the factors have to be equal to 0, or both have to be equal to 0.\r<BR>\n" );
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document.write( "when x - 12 = 0, solve for x to get x = 12.\r<BR>\n" );
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document.write( "when x + 9 = 0, solve for x to get x = -9\r<BR>\n" );
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document.write( "if the values of x are good, then x^2 - 3x - 108 should be equal to 0 when you replace x with either 12 or -9.\r<BR>\n" );
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document.write( "when x = 12, x^2 - 3x - 108 = 12^2 - 3*12 - 108 = 144 - 36 - 108 = 0.\r<BR>\n" );
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document.write( "when x = -9, x^2 - 3x - 108 = (-9)^2 -3*-9 - 108 = 81 + 27 - 108 = 0.\r<BR>\n" );
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document.write( "both solutions are good.\r<BR>\n" );
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document.write( "not sure if that's what you want, but that's what you get.\r<BR>\n" );
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document.write( "here's what the solution looks like on a graph.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" src = \"http://theo.x10hosting.com/2018/081401.jpg\" alt=\"$$$\" >\r<BR>\n" );
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document.write( " </SPAN>\n" );
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