document.write( "Question 101221: $\"%28x%5E2-y%5E2%29%2F%28x%5E4-x%5E3%29\"$ ÷ $\"%28x-y%29%2Fx%5E2\"$ ÷ $\"%28x%5E2%2B2xy%2By%5E2%29%2F%28x%2By%29\"$
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Algebra.Com's Answer #73704 by Edwin McCravy(20060) $\"\"$ $\"About$

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$\"%28x%5E2-y%5E2%29%2F%28x%5E4-x%5E3%29\"$ ÷ $\"%28x-y%29%2Fx%5E2\"$ ÷ $\"%28x%5E2%2B2xy%2By%5E2%29%2F%28x%2By%29\"$
\n" ); document.write( "**the /= the fraction bar not division
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document.write( "We take care of the ÷ 's first in order left to right. So we put\r\n" );
document.write( "parentheses arould the first two fractions so that we do that\r\n" );
document.write( "division first.\r\n" );
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document.write( "( ÷ ) ÷ \r\n" );
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document.write( "Within the parentheses we invert the second fraction and change\r\n" );
document.write( "the division symbol to a multiplication symbol\r\n" );
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document.write( "( · ) ÷ \r\n" );
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document.write( "Now we invert the third fraction and change the division symbol\r\n" );
document.write( "to a multiplication:\r\n" );
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document.write( "Now we don't need the parentheses around the first two any more:\r\n" );
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document.write( " ·  · \r\n" );
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document.write( "Now we indicate the product of all the numerators over the\r\n" );
document.write( "product of all the denominators:\r\n" );
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document.write( "Now we factor the  as ,\r\n" );
document.write( "the  as , and\r\n" );
document.write( "the  as \r\n" );
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document.write( "We cancel the in the top with the  in the bottom.\r\n" );
document.write( "There are two  factors in the top that cancel\r\n" );
document.write( "with the two  factors in the bottom.\r\n" );
document.write( "The  in the top cancels into the  in the bottom,\r\n" );
document.write( "leaving only an  or just  in the bottom. So we have only \r\n" );
document.write( "this left after canceling:\r\n" );
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document.write( "Edwin

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