document.write( "Question 1121222: Melanie has 4 different colored crayons and 2 different boxes as shown below. How many different ways can Melanie put all 4 crayons into the 2 boxes so that each box has at least 1 crayon? \n" ); document.write( "
Algebra.Com's Answer #737022 by ikleyn(52834)\"\" \"About 
You can put this solution on YOUR website!
.
\n" ); document.write( "
\r\n" );
document.write( "The question is closely related to this problem:\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "    How many subsets does the set of 4 elements have ?\r\n" );
document.write( "\r\n" );
document.write( "    The answer is \"2%5E4\" = 16, including empty subset and the improper subset.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "    So, you can place one subset to one of the two boxes and the rest to the other box.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "    But the empty subset and the improper subset are excluded by the condition, so only 16-2 = 14 opportunities are available.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Answer.  14.\r\n" );
document.write( "
\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "This way solving the problem becomes especially useful / (effective) when the original set has MANY elements,\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "so that the direct listing of subsets becomes unpractical.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );