document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1121191>Question 1121191</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve the equation by use of the quadratic formula.\r<BR>\n" );
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document.write( "3x^2=2x+6 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #736971 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=736971\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Rewrite as 3x^2-2x-6=0. This setting everything on one side equalling 0 must be done.<BR>\n" );
document.write( "a=3 b= -2 c= -6<BR>\n" );
document.write( "x=(1/6)(2+/- sqrt(4-4*3*-6)); sqrt term is sqrt (76), or 2 sqrt (19)<BR>\n" );
document.write( "The 2s on the top cancel out part of the 6 below<BR>\n" );
document.write( "x=(1/3)(1+/- sqrt(19))<BR>\n" );
document.write( "This is about +1.7 and -1.1<BR>\n" );
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