document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1121138>Question 1121138</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The probability of it raining tomorrow is 0.12. For the day after, the chance of it not raining is 0.85. By drawing a tree diagram, find the chance of it raining for at least one day out of the tw0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #736966 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=736966\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Note:  I edited the rain probability as 0.15, so the probability of one or the other added to 1.00\r<BR>\n" );
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document.write( "R=0.15-----R 0.15--0.0225(both days)<BR>\n" );
document.write( "-----------NR0.85--0.1275 (1 day)<BR>\n" );
document.write( "NR=0.85---R 0.12--0.1275 (1 day)<BR>\n" );
document.write( "-----------NR 0.85--0.7225 (0 days)\r<BR>\n" );
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document.write( "The probability of at least one rainy day is 0.2775.\r<BR>\n" );
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document.write( "This is the same as 1- probability of no rain either day (0.7225). </SPAN>\n" );
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