document.write( "Question 1121162: If the solution for x of x^2+px+q=0 are the cubes of the solutions for x^2+mx+n=0, express p and q in terms of m and n. \n" ); document.write( "

Algebra.Com's Answer #736944 by ikleyn(52781) $\"\"$ $\"About$

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document.write( "Let    and    be the roots to the second equation.\r\n" );
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document.write( "Then, according to Vieta's theorem,\r\n" );
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document.write( "     +  = - m;   . = n.      (1)\r\n" );
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document.write( "According to the condition, the roots of the first equation are    and  .\r\n" );
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document.write( "Then, according to the Vieta's theorem\r\n" );
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document.write( "    p =  =  =  = ,\r\n" );
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document.write( "    q =  =  = .\r\n" );
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document.write( "Answer.  Under the given conditions,  p =   and  q = .\r\n" );
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