document.write( "Question 1120558: Consider the function below. lim x -> 3 (2x+1)=7
\n" ); document.write( "What values of x guarantee that f(x)=2x+1 is within 0.54 units of 7?
\n" ); document.write( "If x is within _____ units of 3, then f(x) is within 0.54 units of 7.
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Algebra.Com's Answer #736929 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "We need to have
\n" ); document.write( "7-0.54 < 2x+1 < 7+0.54
\n" ); document.write( "6.46 < 2x+1 < 7.54
\n" ); document.write( "5.46 < 2x < 6.54
\n" ); document.write( "2.73 < x < 3.27

\n" ); document.write( "Since this is a linear function, the upper and lower limits are the same distance of 0.27 from 3.

\n" ); document.write( "So to guarantee that 2x+1 is within 0.54 units of 7, x has to be within 0.27 units of 3.

\n" ); document.write( "The preceding is a formal process for finding the solution. Since this is a linear function with a slope of 2, it should be obvious that x needs to be within 0.27 units of 3 for f(x) to be within 0.54 units of 7.
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