document.write( "Question 1121120: Can you help me solve this word problem please?: How many five digit numbers can be formed by using two 4s and three 6s? \n" ); document.write( "

Algebra.Com's Answer #736882 by ikleyn(52879) $\"\"$ $\"About$

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document.write( "Slightly more general formulation is THIS:\r\n" );
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document.write( "    How many distinguishable arrangements (\"words\") can be formed using two letters \"a\" and \"b\".\r\n" );
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document.write( "    The answer is:   =  = 10.\r\n" );
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document.write( "     So you need to take 5! = 120 of all possible permutations of 5 symbols and then divide it by 2! = 1*2  and  by 3! = 1*2*3  \r\n" );
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document.write( "     to account for repeating symbols.\r\n" );
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\n" ); document.write( "\n" ); document.write( "See the lesson\r
\n" ); document.write( "\n" ); document.write( " - Arranging elements of sets containing indistinguishable elements \r
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