document.write( "Question 1121074: Two Coast Guard stations, A and B, are on an east-west line and are 110 km apart. The bearing of a ship from station A is S 56o E, and the bearing of the same ship from station B is S 38o W.\r
\n" ); document.write( "\n" ); document.write( "a) How far is the ship from the east-west line connecting the two Coast Guard stations.
\n" ); document.write( "b) How far is the ship from station A?
\n" ); document.write( "c) How far is the ship from station B?
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Algebra.Com's Answer #736834 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
you can draw triangle ABC as shown in the diagram below:\r
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\n" ); document.write( "\n" ); document.write( "line segment AB of this triangle is equal to a distance of 110 kilometers.
\n" ); document.write( "point A of this triangle is one of the stations.
\n" ); document.write( "point B of this triangle is the other one of the stations.
\n" ); document.write( "point C of this triangle is the location of the ship.\r
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\n" ); document.write( "\n" ); document.write( "the ship is 56 degrees south east of point A and 38 degrees south west of point B, as shown in the diagram.\r
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\n" ); document.write( "\n" ); document.write( "line segment AB in the diagram is a horizontal line because it is on the east-west line of the diagram.\r
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\n" ); document.write( "\n" ); document.write( "the vertical lines emnating from point A and B form a 90 degree with the horizontal line.\r
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\n" ); document.write( "\n" ); document.write( "angle A of triangle ABC is therefore equal to 90 - 56 = 34 degrees.
\n" ); document.write( "angle B of triangle ABC is therefore equal to 90 - 38 = 52 degrees.\r
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\n" ); document.write( "\n" ); document.write( "since the sum of the angles of a triangle is 180 degrees, that makes angle C equal to 94 degrees.\r
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\n" ); document.write( "\n" ); document.write( "110 kilometers is opposite angle C of this triangle.
\n" ); document.write( "line segment b is opposite angle B of this triangle.
\n" ); document.write( "line segment a is opposite angle A of this triangle.\r
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\n" ); document.write( "\n" ); document.write( "by the law of sines, 110 / sin(C) = a / sin(A) = b / sin(B)\r
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\n" ); document.write( "\n" ); document.write( "to find a, you would take 110 / sin(C) = a / sin(A)\r
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\n" ); document.write( "\n" ); document.write( "to find b, you would take 110 / sin(C) = b / sin(B)\r
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\n" ); document.write( "\n" ); document.write( "solve for a to get a = 110 * sin(A) / sin(C)\r
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\n" ); document.write( "\n" ); document.write( "solve for b to get b = 110 * sin(B) / sin(C)\r
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\n" ); document.write( "\n" ); document.write( "these equations become:\r
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\n" ); document.write( "\n" ); document.write( "a = 110 * sin(34) / sin(94) = 61.66142351 kilometers.\r
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\n" ); document.write( "\n" ); document.write( "b = 110 * ain(52) / ain(94) = 86.89284951 kilometers.\r
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\n" ); document.write( "\n" ); document.write( "b is the distance of the ship from location A.\r
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\n" ); document.write( "\n" ); document.write( "a is the distance of the ship from location B.\r
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\n" ); document.write( "\n" ); document.write( "a is equal to line segment BC in the diagram.\r
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\n" ); document.write( "\n" ); document.write( "b is equal to line segment AC in the diagram.\r
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\n" ); document.write( "\n" ); document.write( "note that a = 110 * sin(34) / sin(94) is the same as BC = 110 * sin(34) / sin(94) as shown in the diagram.\r
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\n" ); document.write( "\n" ); document.write( "in other words, a and line segment BC are one and the same line segment.\r
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\n" ); document.write( "\n" ); document.write( "note also that b = 110 * ain(52) / ain(94) is the same as AC = 110 * sin(52) / sin(94) as shown in the diagram.\r
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\n" ); document.write( "\n" ); document.write( "in other words, b and line segment AC are one and the same line segment.\r
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\n" ); document.write( "\n" ); document.write( "your solution is that the distance of the ship from point A is 86.89284951 kilometers and the distance of the ship from point B is 61.66142351 kilometers.\r
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