document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1121078>Question 1121078</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of the digits of a two digits number is 11.if the digits are interchanged. The number they form decreases by 9.find the number  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #736833 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=736833\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "You might want to play around with this a bit to see that it works, since problems like this involving reversing the digits of a 2-digit numbers are common.<br><BR>\n" );
document.write( "You might even want to look at an algebraic proof that the method works....<br><BR>\n" );
document.write( "<b>When the digits of a 2-digit number are reversed, the difference between the original number and the new number is 9 times the difference between the two digits.</b><br><BR>\n" );
document.write( "In this problem, the sum of the digits is 11; and when the digits are reversed the value of the number decreases by 9.  Since 9 is 9*1, the difference between the two digits is 1.<br><BR>\n" );
document.write( "So the two digits have to be 5 and 6; then, since the number decreases when the digits are reversed, the original number was 65. </SPAN>\n" );
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