document.write( "Question 1121026: Two ships leave the dock at 8:00 AM. The first ship travels at a bearing
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document.write( "of N 26° W at 18 miles per hour. The second ship travels at a bearing of
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document.write( "S 43° W at 24 miles per hours. Find the distance between the two ships at
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document.write( "1:00 pm that same day. \r
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document.write( "Round your answer to two decimal places. \n" );
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Algebra.Com's Answer #736768 by Edwin McCravy(20060)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " From 8:00 AM to 1:00 PM is 5 hours.\r\n" ); document.write( "\r\n" ); document.write( "N 26° W means start North and turn 26° toward West,\r\n" ); document.write( "S 43° W means start South and turn 43° toward West.\r\n" ); document.write( "\r\n" ); document.write( "The GREEN line is the path of the first ship.\r\n" ); document.write( "\r\n" ); document.write( "So the length of the GREEN line is rate·time = 18·5 = 90 miles\r\n" ); document.write( "\r\n" ); document.write( "The BLUE line is the path of the second ship.\r\n" ); document.write( "\r\n" ); document.write( "So the length of the BLUE line is rate·time = 24·5 = 120 miles.\r\n" ); document.write( "\r\n" ); document.write( "The angle between the GREEN and BLUE lines is 180°-26°-43° = 111°\r\n" ); document.write( "\r\n" ); document.write( "We use the law of cosines to find the RED line:\r\n" ); document.write( "\r\n" ); document.write( "RED² = GREEN² + BLUE² - 2·GREEN·BLUE·cos(111°)\r\n" ); document.write( "\r\n" ); document.write( "RED² = 90² + 120² - 2·90·120·cos(111°)\r\n" ); document.write( "\r\n" ); document.write( "RED² = 30240.74771\r\n" ); document.write( "\r\n" ); document.write( " RED = 173.90 miles, rounded to 2 decimal places.\r\n" ); document.write( "\r\n" ); document.write( "Edwin\n" ); document.write( " |