document.write( "Question 1121014: 1/15+1/35+1/63+1/99+1/143/+1/199=
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Algebra.Com's Answer #736745 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! 1/15+1/35+1/63+1/99+1/143/+1/199 \n" ); document.write( "---- \n" ); document.write( "= 7/105+3/105 + 1/63+1/99+1/143/+1/199 \n" ); document.write( "= 2/21 + 1/63+1/99+1/143/+1/199 \n" ); document.write( "------ \n" ); document.write( "Combine the terms 2 at a time. \n" ); document.write( "========= \n" ); document.write( "If the last term should be 1/195, a different approach can be used, but it's not my job to figure out what you might have meant.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |