document.write( "Question 101204: A fuel distributor has 161,798 gallons of fuel with 1% sulfur content, which exceeds pollution control standards of 0.6% sulfur content. How many gallons of fuel oil with a 0.1% sulfur content must be added to the 161,798 gallons to obtain fuel oil that complies with the pollution control standards? Round up to the next higher gallon.\r
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Algebra.Com's Answer #73671 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A fuel distributor has 161,798 gallons of fuel with 1% sulfur content, which exceeds pollution control standards of 0.6% sulfur content. How many gallons of fuel oil with a 0.1% sulfur content must be added to the 161,798 gallons to obtain fuel oil that complies with the pollution control standards? Round up to the next higher gallon.\r \n" ); document.write( "\n" ); document.write( "----------------------------- \n" ); document.write( "1% oil DATA: \n" ); document.write( "Amt = 161,798 gals ; Amt of sulfur = 0.01*161,798 = 1617.98 gallons \n" ); document.write( "--------------------- \n" ); document.write( "0.1% oil DATA: \n" ); document.write( "Amt = x gals ; Amt of sulfur = 0.001x gallons \n" ); document.write( "---------------------- \n" ); document.write( "0.6% Mixture DATA: \n" ); document.write( "Amt = 161798+x ; Amt of sulfur = 0.006(161798-x) = 970.788 - 0.006x gals \n" ); document.write( "----------------------- \n" ); document.write( "EQUATION: \n" ); document.write( "sulfur + sulfur = sulfur \n" ); document.write( "1617.98 + 0.001x = 970.788 - 0.006x \n" ); document.write( "647.192 = 0.005x \n" ); document.write( "x = 129,438.4 gallons of 0.1% oil must be added to bring the tank down \n" ); document.write( "to 0.6% sulfur content. \n" ); document.write( "============== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |