document.write( "Question 1120966: A student plans to spend ₦200 on p notebooks. But the price of the notebooks had increased by ₦10. As a result, the number of notebooks the student could buy was reduced by 1. Find the price of each notebook before the increase. \n" ); document.write( "

Algebra.Com's Answer #736693 by ikleyn(52788) $\"\"$ $\"About$

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document.write( "\"p\" notebooks costed N200  ====>  hence, one notebook price was  before increasing.\r\n" );
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document.write( "After increasing, one notebook price becomes , and the difference is N10.\r\n" );
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document.write( "Equation\r\n" );
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document.write( "     -  = 10\r\n" );
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document.write( "To solve it, multiply both sides by  p*(p-1). You will get\r\n" );
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document.write( "    200*p - 200*(p-1) = 10p*(p-1)\r\n" );
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document.write( "    200p - 200p + 200 = 10p^2 - 10p\r\n" );
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document.write( "    10p^2 - 10p - 200 = 0\r\n" );
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document.write( "    p^2 - p - 20 = 0\r\n" );
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document.write( "    (p-5)*(p+4) = 0.\r\n" );
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document.write( "The only positive solution is  p= 5.\r\n" );
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document.write( "Answer.  Before price increasing, one notebook cost was   = N40.\r\n" );
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\n" ); document.write( "To see many other similar problems solved by the same method, look into the lesson\r
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