document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1120960>Question 1120960</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemical company makes two brands of antifreeze. The first brand is <BR>\n" );
document.write( "35%<BR>\n" );
document.write( " pure antifreeze, and the second brand is <BR>\n" );
document.write( "85%<BR>\n" );
document.write( " pure antifreeze. In order to obtain <BR>\n" );
document.write( "50<BR>\n" );
document.write( " gallons of a mixture that contains <BR>\n" );
document.write( "65%<BR>\n" );
document.write( " pure antifreeze, how many gallons of each brand of antifreeze must be used?<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #736680 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=736680\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "An easy way to solve mixture problems like this, in which two ingredients are being mixed, is to use the fact that the ratio in which the two ingredients must be mixed is exactly determined by where the percentage of the mixture lies between the percentages of the two ingredients.<br><BR>\n" );
document.write( "The percentages of the two ingredients are 35% and 85%; the percentage of the mixture is 65%.<br><BR>\n" );
document.write( "65% is three-fifths of the way from 35% to 85%.  (65-35 = 30; 85-35 = 50; 30/50 = 3/5)<br><BR>\n" );
document.write( "So 3/5 of the mixture must be the ingredient with the higher percentage of antifreeze.<br><BR>\n" );
document.write( "So 3/5 of the 50 gallons, or 30 gallons, should be the 85% antifreeze; the other 2/5, or 20 gallons, should be the 35% antifreeze.<br><BR>\n" );
document.write( "Check:<br><BR>\n" );
document.write( "(.85)(30)+(.35)(20) = 25.5+7 = 32.5<BR>\n" );
document.write( "(.65)(50) = 32.5 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );