document.write( "Question 1120907: Admission to a school play costs $12.50. Form an inequality and solve it to find the maximum number of ticket Jun Wei can buy with $250. \n" ); document.write( "
Algebra.Com's Answer #736602 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "Let x be the number of tickets Jun Wei purchases.
\n" ); document.write( "The value of x is some positive whole number.\r
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\n" ); document.write( "\n" ); document.write( "1 ticket costs 12.50*1 = $12.50
\n" ); document.write( "2 tickets cost 12.50*2 = $25
\n" ); document.write( "3 tickets cost 12.50*3 = $37.50
\n" ); document.write( "4 tickets cost 12.50*4 = $50
\n" ); document.write( "and so on...\r
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\n" ); document.write( "\n" ); document.write( "The general pattern is
\n" ); document.write( "x tickets cost 12.50*x dollars\r
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\n" ); document.write( "\n" ); document.write( "The expression 12.50*x represents the total amount of dollars Jun Wei spends. We want this total to be $250 or smaller. \r
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\n" ); document.write( "\n" ); document.write( "\"Total+%3C=+250\"\r
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\n" ); document.write( "\n" ); document.write( "\"12.50%2Ax+%3C=+250\"\r
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\n" ); document.write( "\n" ); document.write( "\"12.50%2Ax%2F12.50+%3C=+250%2F12.50\" Divide both sides by 12.50 to undo the multiplication.\r
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\n" ); document.write( "\n" ); document.write( "\"x+%3C=+20\"\r
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\n" ); document.write( "\n" ); document.write( "The maximum number of tickets Jun Wei can buy is 20 tickets.\r
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\n" ); document.write( "\n" ); document.write( "Note how 12.50*20 = 250 which is the max amount that can be spent. That helps confirm the answer.
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