document.write( "Question 1120901: Two train stations, A and B, are 300km apart. Two trains leave A and B simultaneously and proceed at constant speeds to the other station. The train from A reaches station B nine hours after the trains have met, and the train from B reaches the station A four hours after the trains have met. Find the speed of each train. \n" ); document.write( "
Algebra.Com's Answer #736598 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let s[A] = train A痴 speed
\n" ); document.write( "Let s[B] = train B痴 speed
\n" ); document.write( "Let t = time in hrs for them to meet
\n" ); document.write( "\"+s%5BA%5D%2At+\" = distance A travels until they meet
\n" ); document.write( "\"+s%5BB%5D%2At+\" = distance B travels until they meet
\n" ); document.write( "覧覧覧覧覧覧覧覧覧覧覧覧-
\n" ); document.write( "You are given that
\n" ); document.write( "\"+s%5BA%5D%2A%28+t+%2B+9+%29+=+300+\"
\n" ); document.write( "\"+s%5BB%5D%2A%28+t+%2B+4+%29+=+300+\"
\n" ); document.write( "\"+s%5BA%5D%2At+%2B+s%5BB%5D%2At+=+300+\"
\n" ); document.write( "覧覧覧覧覧覧覧-
\n" ); document.write( "\"+s%5BA%5D+=+300%2F%28+t+%2B+9+%29+\"
\n" ); document.write( "\"+s%5BB%5D+=+300%2F%28+t+%2B+4+%29+\"
\n" ); document.write( "覧覧覧覧覧覧覧-
\n" ); document.write( "\"+300t%2F+%28+t+%2B+9+%29+%2B+300t+%2F%28+t+%2B+4+%29+=+300+\"
\n" ); document.write( "\"+t%2F%28+t+%2B+9+%29+%2B+t%2F%28+t+%2B+4+%29+=+1+\"
\n" ); document.write( "multiply both sides by \"+%28+t+%2B+9+%29%2A%28+t+%2B+4+%29+\"
\n" ); document.write( "\"+t%2A%28+t+%2B+4+%29+%2B+t%2A%28+t+%2B+9+%29+=+%28+t+%2B+4+%29%2A%28+t+%2B+9+%29+\"
\n" ); document.write( "\"+t%5E2+%2B+4t+%2B+t%5E2+%2B+9t+=+t%5E2+%2B+4t+%2B+9t+%2B+36+\"
\n" ); document.write( "\"+t%5E2+=+36+\"
\n" ); document.write( "\"+t+=+6+\"
\n" ); document.write( "覧覧覧覧
\n" ); document.write( "\"+s%5BA%5D+=+300%2F%28+6+%2B+9+%29+\"
\n" ); document.write( "\"+s%5BA%5D+=+20+\" km/hr
\n" ); document.write( "And
\n" ); document.write( "\"+s%5BB%5D+=+300%2F%28+6+%2B+4+%29+\"
\n" ); document.write( "\"+s%5BB%5D+=+30+\" km/hr
\n" ); document.write( "
\n" ); document.write( "
\n" );