document.write( "Question 1120885: In 1995​, funding for a program increased by 0.75 billion dollars from the funding in 1994. In 1996​, the increase was 0.15 billion dollars over the funding in 1995. For those three years the funding was 9.48 billion dollars. How much was funded in each of these three​ years? \n" ); document.write( "
Algebra.Com's Answer #736588 by Theo(13342)\"\" \"About 
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in 1994, the funding was x.
\n" ); document.write( "in 1995, the funding was x + .75 billion.
\n" ); document.write( "in 1996, the funding was x + .75 + .15 billion.\r
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\n" ); document.write( "\n" ); document.write( "for the 3 years, the funding ws 9.48 billion dollars.\r
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\n" ); document.write( "\n" ); document.write( "sum up all the funding for the 3 years and you get 3 * x + 2 * .75 + 1 * .15 = 3 * x + 1.65 billion.\r
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\n" ); document.write( "\n" ); document.write( "3 * x + 1.65 = 9.48\r
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\n" ); document.write( "\n" ); document.write( "subtract 1.65 from both sides of this equation to get 3 * x = 7.83.\r
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\n" ); document.write( "\n" ); document.write( "solve for x to get x = 7.83 / 3 = 2.61 billion.\r
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\n" ); document.write( "\n" ); document.write( "in 1994, the funding was 2.61 billion.
\n" ); document.write( "in 1995, the funding was 2.61 + .75 = 3.36 billion.
\n" ); document.write( "in 1996, the funding was 3.36 + .15 = 3.51 billion.\r
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\n" ); document.write( "\n" ); document.write( "2.61 + 3.36 + 3.51 equals total funding of 9.48 billion.\r
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\n" ); document.write( "\n" ); document.write( "solution checks out.\r
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\n" ); document.write( "\n" ); document.write( "solution is:\r
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\n" ); document.write( "\n" ); document.write( "2.61 billion in 1994.
\n" ); document.write( "3.36 billion in 1995.
\n" ); document.write( "3.51 billion in 1996.\r
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