document.write( "Question 1120853: a customer bought a dozen of pieces of fruits (apples and oranges) for 1.32 dollars. If an apple cost 3 cents more than an orange and more apples than oranges were purchased, how many pieces of each kind were bought? \n" ); document.write( "
Algebra.Com's Answer #736569 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! a customer bought a dozen of pieces of fruits (apples and oranges) for 1.32 dollars. \n" ); document.write( " If an apple cost 3 cents more than an orange and more apples than oranges were purchased, \n" ); document.write( " : \n" ); document.write( "let p = cost of the oranges \n" ); document.write( "then \n" ); document.write( "(p+3) = cost of the apples \n" ); document.write( ": \n" ); document.write( "No. of apples are at least 7. (apples are more than the oranges) \n" ); document.write( "let's try 8 apples 4 oranges, friendly numbers \n" ); document.write( "8(p+3) + 4p = 132 \n" ); document.write( "8p + 24 + 4p = 132 \n" ); document.write( "8p + 4p = 132 - 24 \n" ); document.write( "12p = 108 \n" ); document.write( "p = 108/12 \n" ); document.write( "p = 9 cents for oranges \n" ); document.write( "then \n" ); document.write( "9 + 3 = 12 cents for apples \n" ); document.write( "\"How many pieces of each kind were bought? \" \n" ); document.write( "8 apples, 4 oranges \n" ); document.write( " \n" ); document.write( " |