document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=100783>Question 100783</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A train leaves the station at 6:00 P.M. traveling west at 80 mi/h.  On a parallel track, a second train leaves the station 3 hours later traveling west a 100 mi/h.  At what time will the second train catch up with the first? \r<BR>\n" );
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document.write( "A passenger train's speed is 60 mi/h, and a freight train's speed is 40 mi/h.  The passenger train travels the same distance in 1.5 h less time than the freight train. How long does each train take to make the trip? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #73656 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=73656\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A train leaves the station at 6:00 P.M. traveling west at 80 mi/h. On a parallel track, a second train leaves the station 3 hours later traveling west a 100 mi/h. At what time will the second train catch up with the first?<BR>\n" );
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document.write( "Let t = traveling time of the 1st train, when the 2nd train catches up<BR>\n" );
document.write( "Then<BR>\n" );
document.write( "(t-3) = traveling time of the the 2nd train.<BR>\n" );
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document.write( "When this occurs, both trains will have traveled the same distance; <BR>\n" );
document.write( "Write a distance equation: Dist = speed * time<BR>\n" );
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document.write( "100(t-3) = 80t<BR>\n" );
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document.write( "100t - 300 = 8t<BR>\n" );
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document.write( "100t- 80t = +300<BR>\n" );
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document.write( "20t = 300<BR>\n" );
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document.write( "t = 300/20<BR>\n" );
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document.write( "t = 15 hrs<BR>\n" );
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document.write( "Time = 6 PM + 15 hrs = 9 AM the next day<BR>\n" );
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document.write( "Check solution by find the distance traveled by each train:<BR>\n" );
document.write( "80 * 15 = q1200 mi<BR>\n" );
document.write( "100 * (15-3) = 1200 mi<BR>\n" );
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document.write( "A passenger train's speed is 60 mi/h, and a freight train's speed is 40 mi/h. The passenger train travels the same distance in 1.5 h less time than the freight train. How long does each train take to make the trip?<BR>\n" );
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document.write( "Use another distance equation:<BR>\n" );
document.write( "Let t = pass train time<BR>\n" );
document.write( "then<BR>\n" );
document.write( "(t+1.5) = freight train time<BR>\n" );
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document.write( "60t = 40(t+1.5) <BR>\n" );
document.write( "60t = 40t + 60<BR>\n" );
document.write( "60t - 40t = 60<BR>\n" );
document.write( "t = 60/20<BR>\n" );
document.write( "t = 3 hrs for the pass train, and 4.5 hrs for the freight<BR>\n" );
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document.write( "Check solution see if the distance is the same:<BR>\n" );
document.write( "60 * 3 = 180 mi<BR>\n" );
document.write( "40 * 4.5 = 180 mi<BR>\n" );
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